(1b) ∫² (2x + 9)dx -² 2x²/2+9x + c|²_¹ x² + 9x + c|²_¹ (2² + 9(2) + C) – ((-1)² + 9 (-1)+ c) (4+18+c) – (1-9+C) (22 + C) – (-8 + C) 22+C + 8 – C =30. ==================================== (2a) To calculate u; 18+5+12+u=52 35+u=52 u=52-32=17 u=17
To calculate v 6+5+12+v=35 23+v=35 v=35-23=12 v=12
To calculate w w+18+17+6+5+12+12 =100 w+70=100 w=100+70=30 w=30
(2b) at least two means =18+6+5+12=41 ; 41 tourist travelled by at least two means of transportation. w=100+70=30 w=30
(2b) at least two means =18+6+5+12=41 ; 41 tourist travelled by at least two means of transportation. ===================================== (3a) (i)median =6+6/2=12/2=6 (ii)median + range = 6+7=13 Range = highest value – lowest value = 10-3=7
(3b) Pr(both pass) =2/5*3/4=6/20=3/10. ===================================== (4a) x²+3x-28=0 x²+7x-4x-28=0 x(x+7)-4(x+7)=0 (x-4)(x+7)=0 x-4=0 or x+7=0 x=0+4 or x=0-7 x=4 or -7
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