# Waec Further Maths Answers 2021 for 9th September

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This is another timely post to inform you of the **Waec 2021 Further Mathematics Obj/Essay questions and answers. **As far as I’m concern, every student wants to have an excellent result in Waec and that is why some of them do go the extra mile in having their result be excellent.

Like it has always been our nature to provide you with the current questions and answers before the exams commence, we have also made available the updated **Further Mathematics Obj/Essay Waec 2021 Obj/Essay **questions for all candidates of the 2021 Waec who are writing Agricultural science. If you got our English Language WAEC questions and answers, then you will thank us again for this one

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Though a lot of persons may not really use the W**aec 2021 Further Mathematics Obj/Essay questions and answers **because of certain things like the fact that Agricultural science is not a course offered by everyone and most persons prefer Animal Husbandry or fishery to agricultural science.

In this post, we will provide you with the forthcoming W**aec 2021 Further Mathematics Obj/Essay questions, **and not only that, we will do well to endeavor that there is a complete W**aec 2021 Further Maths Obj/Essay answers **provided by experts and examiners who have been teaching and answer **Further Maths Obj/Essay past questions and answers.**

For candidates who are offering agricultural science, it is important to make the August/September** agric question **for you to have it before the examination start or before you are given the **Further Mathematics Obj/Essay quiz **questions.

## Waec Further Mathematics Answers 2021 Obj/Essay for 9th September.

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#### Thursday, 9th September 2021

- Further Mathematics/Mathematics(Elective) 2 (Essay) 9:30am. –12:00noon.
- Further Mathematics/Mathematics(Elective) 1 (Objective) 3:30pm. –5:00 pm.

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It is also important that you study the objective questions on agricultural science carefully as though there are objective questions, the questions seen there are a bit technical and a little sense should be applied to it when solving out for the questions.

One of the tools which students can employ in answering the Waec 2021 Further Mathematics Obj/Essay questions excellently well is for candidates to make effective use of the Waec past questions on agricultural science.

The Further Mathematics Obj/Essay question and answer for Waec 2021 are not really difficult, but the questions are a bit technical and candidates should reason very well before trying to provide answers to them to avoid the mistakes many students did during when the chemistry waec question 2021 was given.

From the questions above, we can also see that a good number of questions are drawn from the agriculture past papers 2016 and that is why we do emphasize the effective study of the past questions and answers.

For those who wrote the Further Maths Obj/Essay, you will realize that the questions were a bit difficult though the specimen given was common.

The agricultural science questions for WAEC 2021 are very simple and straightforward questions that require a little reason. Though answers are given to the waec 2021 Further Mathematics Obj/Essay questions, you should also endeavor that you solve the questions closely and provide answers yourself using the past questions and answers.

**Last Year WAEC Further Mathematics Answers**

1CBBDCAADCB

11DCBDCBCDCC

21ABDCDABBCB

31CDCADBCAAD

=========================

12)

P:F=4:1 =4x+1x=100

5x=100

x=100/5

x=20

pass=20*4=80%

fail= 20*1=20%

p(pass)=80/100=0.8

p(fail)=20/100=0.2

n=7

12ai)

P(at least 3passed)

P=0.8

Q=0.2

P(x=r)=n(rP^rq^n-r

P(x>/3)=1-P(x<2) P(x<2)=P(x=0)+P(x=1)+P(x=2) P(x=0)=7dgree (0.8)degree (0.2)^7 P(x=0)=0.0000128 P(x=1)=^7( (0.8)^1 (0.2)^6 =0.0003584 P(x<2)=7^C2 (0.8)^2 (0.2)^5 =0.0043008 P(X<2)=0.0000128+0.0003584+0.004300 =0.004672 P(x>3)=1-0.004672

=0.995321

=0.10(2d.p)

12aii)

P(between 3 and 6 failed)

P=0.2

q=0.8

P(36)

P(x=3) + P (x=4)+p(x=5)+P(x=6)

p(x=3) 7^C3 (0.2)^3 (0.8)^4

=0.114688

p(x=4)=7^C4 (0.2)^4 (0.8)^3

0.028672

P(x=5)=7^C5 (0.2)^5 (0.8)^2

=0.0043008

P(x=6)=7^C6 (0.2)^6 (0.8)^1

=0.0003584

p(36)

=0.114688+0.028672+0.0043008

+0.0003584

=0.1480192

=0.15(2d.p)

==================

4)

(x^2+5x+1)sqroot(2x^3+mx^2+nx+11)=(2x-5)

remainder:30x+16

(x^2+5x+1)(2x-5)

=2x^3+10x^2+2x-5x^2-25x-5

=2x^3+10x^2-5x^2-25x-5

=2x^3+5x^2-23x+30x+16-5

=2x^3+5x^2+7x+11

Therefore m=5, n=7

=================

5a)

pr(age)=4/5

pr(fully)=3/4

pr(must)=2/3

pr(age not admitted)=1-4/5

=1/5

pr(fully not admitted)=1-3/4

=1/4

pr(must not admitted)=1-2/3

=1/3

Therefore pr(none admitted)=1/5*1/4*1/3

=1/60

5b)

pr(only age and fully gained admission)=4/5*3/4*1/3

=1/5

================

12a)

tabulate

Marks| 1-10, 11-20, 21-30, 31-40, 41-50,51-60, 61-70, 71-80, 81-90, 91-100

F| 3, 17, 41, 85, 97, 115, 101, 64, 21, 6

C.B| 0.5-105, 10.5-205, 20.5-305, 30.5-405,40.5-505, 50.5-605, 60.5-705, 70.5-805,80.5-905, 90.5-1005

C.F| 0+3=3, 3+17=20, 20+41=61, 61+85=146,146+77=243, 243+115=358, 358+101=459,459+64=523, 523+21=544, 544+6=550

=================

11a)

Given:

f(x)={(4x-x^2)dx

f(x)=2x^2 – x^3/3 + K

f(3)=2(3)^2 – (3)^2/3 + K =21

18 – 9 + K=11

9+K=21

K=21-9

K=12

Therefore

f(x)= -x^3 + 2x^2 + 12

11b)

i) Tn=a+(n-1)d

T2=a+(2-1)d

T2=a+d

T4=a+3d

T8=a+7d

GP

Tn=ar^n-1

T1=ar^1-1

T2=ar^2-1=ar

T3=ar^2

a+d=a …..equation (1)

a+3d=ar …..equation (2)

a+7d=ar^2 …..equation (3)

T3+T5=20

a+2d+a+4d=20

2a+6d=20

a+3d=10 …..equation (4)

…..equation (2)/…..equation (1)

ar/a=a+3d/a+d

r=a+3d/a+d

…..equation (3)/…..equation (2)

ar^2/ar=a+7d/a+3d

r=a+7d/a+3d

but r=r

a+3d/a+d=a+7d/a+3d

(a+3d)^2=(a+d)(a+7d)

a^2+6ad+ad^2

a^2+7ad+ad+7d^2

a^2+8ad+7d^2

a^2+6ad+9d^2=a^2

+8ad+7d^2

6ad+9d^2=8ad+7d^2

6ad-8ad=7d^2-9d^2

-2ad=2d^2

ad=dd

a=d

===================

(9a)

1/1-cos tita + 1/1+cos tita

=1+cos tita + 1-cos tita//(1-cos tita) (1+cos tita)

= 2/1+cos tita – cos tita – cos^2 tita

= 2/1-cos^2 tita

Recall that :

Cos^2 tita + sin^2 tita = 1

.:. Cos^2 tita = 1-sin^2 tita

.:. 1/1-cos^2 tita + 1/1+cos tita

= 2/1-(1-sin^2 tita)

(9b)

At stationary points,

dy/dx=0.

y=x^0(x-3)

Let u=x^2,v=x-3.

du/dx=2x dv/dx=1.

dy/dx= Udv/dx + Vdu/dx

dy/dx=x^2(1)+(x-3)(2x)

.:. dy/dx=x^2+2x^2-6x

dy/dx=3x^2-6x

At stationary point,

dy/dx=0..

.:.3x^2-6x=0

Equation of line=> 3x^2-6x=0

==================

14ai)

**SKETCH THE DIAGRAM**

14aii)

Using lami’s theory

T1/sin60=T2/sin30

48N/sin60=T2/sin30

48N/0.8660=T2/0.5

0.5(48)/0.8660=T2(0.8660)/0.8660

T2=24/0.8660

T2=27.7N

14b)

Using the equation of motion

H=U^2/2g

H=(20)^2/2*10

=20*20/20

H=20m

Timetaken to reach the maximum height

S=Ut+1/2at^2

20=0+1/2(100)t^2

20/5=5t^2/5

t^2=4

t=sqroot4

t=2S

================

10a)

i) (x^2-1) (x+2)=0

(x-1) (x+1) (x+2)

x=1, or -1 or -2

ii) 2x-3/(x-1)(x+1)(+2)

=A/x-1+B/x+1+C/x+2

2x-3=A(x+1)(x+2)+B(x-1)(x+2)

+C(x-1)(x+1)

let x+1=0,x=-1

2(-1)-3=B(-1-1)(-1+2)

-5/2=-2B/-2 B=5/2

let x-1 =0 x=1

2(1)-3=A(1+1)(1+2)

-1=CA, A=-1/6

Let x+2=0 x=-2

2(-2)-3=C(-2-1)(-2+1)

-7=3C, C=-7/3

10b)

X1 Y2

(3, 1)

r=sqr(x2-x1)^2+(y2-y1)^2

r=sqr(3+3)^2+(1-1)^2

r=sqr6^2+0=sqr36=6

the equatuon of a circle

(x-a)^2+(y-b)^2=r^2

(x-(-3))^2+(y-1)^2=6^2

(x+3)^2+(y-1)^2=36

x^2+6x*9+y^2-2y+1=36

x^2+y^2+6x-2y+9+1-36=0

x^2+y^2+6x-2y-26=0

===================

1a)

g(x)=y

y=x+6

x=y-6

g^- f(x-6)

=4-5(x-6)/2=4-5x+30/2

=34-5x/2

1b)

coodinate=(x1+x2/2 ,y1+y2/2)

=(7-2/2,7-5/2)=(5/2,2/2)

=(5/2,1)

This is the * WAEC 2021 Further Mathematics questions* and answers/expo/runs (obj/theory) for all students who are preparing to write Further Mathematics subject in the West African Examination Council (WAEC) in May/June 2021.

WAEC Further Mathematics 2021 Practical Questions & Answers are required by students who finished writing either JAMB or WAEC exam in May/June.

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## SEE WAEC 2021/2022 FURTHER MATHEMATICS OBJ/THEORY QUESTIONS & ANSWER

When writing the Further Mathematics subject in WAEC exams, you must have read from the Further Mathematics syllabus printed and published by the Ministry of Education and studied your past question papers with answers available in bookshops and online for free.

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### HOW TO PASS WAEC FURTHER MATHEMATICS 2021 EXAMINATION

You can pass this Further Mathematics 2021 Essay & OBJ (Test of Orals) without copying Questions/Answers from the internet. All you have to do is to buy past questions papers and answers from book shops near you. If you can’t afford it, download them online then use the WAEC syllabus 2021/20 to study them very well. Solve the questions before the exam date then you will be prepared to write the exam. Enter the exam will confidence and answer all questions that will be asked.

## DOWNLOAD **WAEC 2021 FURTHER MATHEMATICS QUESTIONS** & ANSWERS HERE

**WAEC 2021 FURTHER MATHEMATICS QUESTIONS**

Finally, download Further Mathematics Answers from your textbooks and notebooks into your head by reading very hard before entering the examination hall. You have been advised accordingly.

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The **waec 2021 Further Mathematics Obj/Essay questions and answers **still have the same format as previous years

Please take note that there are questions provided here for the **waec 2021 Further Mathematics Obj/Essay questions and answers **and they contain both questions for Obj and theory.

Mathematics

Government

Economic 2an1 Agric Science 2an1