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Neco Chemistry 2022 Answers 25th July 2022

Neco Chemistry Objective & Essay Answers 2022 for 25th July 2022 with questions 100% verified official questions and answers for senior secondary schools.

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EXAM: Neco
SUBJECT: Chemistry
PIN: 711
WEBSITE: expobite.net

Kindly search EXPOBITE ANSWER PAGE on google and put the above password.
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CHEMISTRY OBJ
01-10: EBAAAAAACC
11-20: BCBCACADCA
21-30: AACBDDAACD
31-40: CCACCACCDE
41-50: EDCCDDBDAC
51-60: CBACCDCBCD

Completed!
=================================
CHEMISTRY ESSAY
(1ai)
(i) KAl(SO₄)₂. 12H₂O
(ii) Na₂SO₄

(1aii)
Number of moles of sodium reascted = reacting mass/molar mass
= 3.6/23
= 0.1565moles
Number of moles of oxygen reacted = (1/4) x Number of sodium
= 1/4 x (3.6/23)
= 0.03913
Reacting mass of oxygen = Number of moles x molar mass
= 0.03913 x (16×2)
= 1.252grams

(1bi)
Air in gaseous form is first passed through caustic soda to remove CO₂. It is compressed and cooled until ut becomes a liquid at -200°C. It is then led to a fractionating column. On distillation, Nitrogen which has a lowet boiling point of -196°C is evolced first leaving behind Oxygen in liquid form. Further heating converts the liquid to a gas at -183°C.

(1bii)
(i) It is used for combustion
(ii) It is used for artificial respiration

(1biii)
This is because room temperature is warmer

(1biv)
(i) Methyl orange
(ii) Phenophthalein

(1ci)
An ion is an atom or molecule which has a net electric charge due to the loss or gain of one or more electrons.

(1cii)
HCl gas doesn’t contain ions

(1cii)
(i) Noble gases: Neon, Helium
(ii) Halogens: Iodine, Fluorine
(iii) Alkaline earth metals: Calcium, Magnesium

(1civ)
Halogens attain stable octet configuration by accepting an electron from donors Group I elements.

(1di)
A sol is a colloid where solid particles are dispersed in liquid medium.

(1dii)
Jelly

(1diii)
(i) Acid-base titrations are used to determine the percentage purity of a substance
(ii) Acid-base titrations are important to determine the number of water molecules in a hydrate.
°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°
(2ai)
A molar solution of a compound contains one mole or the molar mass of the compound in one dm³ of the solution.

(2aii)
(i) Identification of gases
(ii) Identification of acidic and metallic radicals

(2aiii)
(i) Purification of bauxite
(ii) Electrolysis of alumina

(2bi)

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(2bii)
This is because of the presence of copper which is a transition metal

(2bii)
(i) Methanamide is a liquid while the rest amides are crystalline solids
(ii) Melting points and boiling points of aides are much higher than expected.

(2ci)
(i) Heavy chemicals are produced in very large quantities in industries While fine chemicals are produced in small quantities for specific purposes
(ii) Heavy chemicals are in a crude state While fine chemicals are purified.

(2cii)
(i) Million’s reagent
(ii) Feeling’s solution

(2ciii)
Graham’s law of diffusion states that at a constant temperature and pressure the rate of diffusion of a gas is inversely proportional to the square root of its density.

(2civ)
RO₂/RCH₄ = √(MCH₄/MO₂)
5/(200/t) = √[(12+4)/(16×2)]
5t/200 = √16/32
t/40 = 1/√2
t = 40/√2
t = (40/√2) × (√2/√2)
t = 20√2 seconds
Time taken = 28.28 seconds.


°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°
(5)



°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°
(6a)



(6b)

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Neco Chemistry Answers 2022: here are the verified Neco 2022 Chemistry Objective & Essay questions and answers for SS3 students for Monday 25th July 2022. Neco 2022 Chemistry Objective & Essay Questions and Answers.

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Monday 25th July 2022

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Neco 2022 Chemistry Objective & Essay Questions and Answers

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(2a)
[TABULATE]

=TEST=
C + Distilled water

=OBSERVATION=
It dissolves completely to give a light green solution.

NECO 2022 Chemistry (Essay & OBJ) Questions & Answers
NECO Chemistry Questions and Answers 2022 (100% Sure

=INFERENCE=
Soluble salt.

(2ai)
=TEST=
Solution C + NaOH in drops and in excess + Heat gently

=OBSERVATION=
A dirty green precipitate is formed which remains insoluble in excess.
Effervescence occurs in which a colourless gas with a pungent smell which turns red litmus blue is given off.

=INFERENCE=
Fe²⁺ is present.
NH₃ gas form.
NH₄⁺ is present.

(2aii)
=TEST=
Solution + BaCl₂ + dilute HCL in excess

=OBSERVATION=
A white precipitate is formed.
The white precipitate remains insoluble and gives a white dense.

=INFERENCE=
SO₄²⁻, CO₃²⁻, SO₃²⁻, is present.
SO₄²⁻ confirmed.

(2b)
Cations → Fe²⁺ and NH₄⁺
Anions → SO₄²⁻

(3a)
Sulphur Dioxide Solution Turns Acidified Potassium Chromate Solution green Where As carbon dioxide Shows no Change

(3bi)
(I) H2 ; downward displacement of water
(II) NH3; downward displacement of air
(III) HCL; upward displacement of air

(3bii)
(I) Hydrogen gas(H2) is collected by the downward displacement of water because It is insoluble in water and It form an explosive mixture with air.

(II) Ammonia gas(NH3) is collected by downward displacement of air because it is lighter than air

(III) HCl gas is collected by upward displacement of air because it is 1.28 times heavier than air.

(3c)
(i) Distillation
(ii) Filtration followed by evaporation to dryness

(3d) This is because KCl react with NaHCO₃ to form two salts

(3bi)
(I) H2 ; downward displacement of water
(II) NH3; downward displacement of air
(III) HCL; upward displacement of air

(3bii)
(I) Hydrogen gas(H2) is collected by the downward displacement of water because It is insoluble in water and It form an explosive mixture with air.

(II) Ammonia gas(NH3) is collected by downward displacement of air because it is lighter than air

(III) HCl gas is collected by upward displacement of air because it is 1.28 times heavier than air.

(3c)
(i) Distillation
(ii) Filtration followed by evaporation to dryness

1. The reaction of carbide with water gives

A. Ethyne✅✅
B. Ethene
C. Ethane
D. Ethanal
equation to reaction
C2+H2O=C2H2+02
and also the general formula for alkyne is CnH2n-2

2. The general formula of alkanones is

A. RCHO
B. RCOR’✅
C. RCOOH
D. RCOOR

Alkanones also known as ketones have the general formula RCOR’

3. A second alkanol can be oxidized to give an

A. Alkanone✅✅
B. Alkyne
C. Alkanoic acid
D. Alkanal

When an secondary alcohol is treated with acidified KMnO4, or K2Cr2O7, they yield an alkanone

4. Which of the following substances are all made by the process of polymerization?

A. Nylon and soap
B. Ethanoic acid margarine and ethanol
C. Nylon and artificial rubber✅✅
D. Soap and butane
E. Margarine and nylon

5. If an organic compound decolorizes bromine water then the compound is?

A. Saturated
B. Supersaturated
C. Unsaturated✅✅
D. A solid
E. Protonated

NECO Chemistry Practical Questions and Answers 2022 (100
NECO Chemistry Questions and Answers 2022 (100%)

6. Which of the following types of reactions takes place between C2H4 and the halogens?

A. Substitution
B. Polymerization
C. Addition✅✅
D. Saponification
E. Oxidation

7. The alkanol obtained from the production of soap is

A. Ethanol
B. Glycerol✅✅
C. Methanol
D. Propanol
E. Glycol

The alcohol we use to make fats is ‘glycerol’ When fats or oils are hydrolysed using alkaline hydrolysis, a soap and glycerol are formed:

fats (or oil) + NaOH => soap + glycerol

8. The three-dimensional shape of methane is

A. Hexagonal
B. Trigonal
C. Linear
D. Tetrahedral✅✅
E. Cubical

9. An element that can exist in two or more different structural forms which possess the same chemical properties is said to exhibit.

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A. Polymerism
B. Isotopy
C. Isomorphism
D. Isomerism
E. Allotrophy✅✅

Allotropy is the existence of two or more atoms of an element having the same physical states but different physical or structural forms.

10. The hybridization of the carbon atom in ethyne is

A. Sp⁴
B. Sp³
C. Sp²
D. Sp✅✅
E. S

Ethane sp³ hybridization
Ethene sp² hybridization
Ethyne sp hybridization

Theory-Answers

(1a)
A molecular formula consists of the chemical symbols for the constituent followed by numeric subscripts showing the number of atoms of each element present while structural formula consists of symbols for the atoms connected by short lines that represent chemical bonds.

(1b)
(i) Screening effect
(ii) Size of atom
(iii) Nuclear change

(1c)
(i) The reaction must proceed both forward and backward i.e reversible
(ii) DG = O

(1d)
(i) B
(ii) It has the least ionization energy among the three

(1e)
Graham’s law of diffusion states that the rate of diffusion of a gas is inversely proportional to the square root of their densities provided other conditions remained constant

(1f)
(i) Na2SO4. Mg(NO3)2
(ii) CaCO3

(1g)
(i) Protein – Addition polymer
(ii) Perspex – Condensation polymer
(iii) Nylon – Condensation polymer

(1h)
Atomic radius can be defined as the half distance between the nucleus of two covalently bonded atoms.

(1i)
Ethanol has a higher boiling point than propane because it has stronger force of attraction than propane which has a weak van der waal’s force.

Neco Chemistry Answers 2022 Monday 25th July 2022
NECO Chemistry Questions and Answers 2022 (Theory & Obj

(1j)
(i) It aids the digestion of food
(ii) It aids the action of enzymes
(iii) It controls the availablity of nutrients
==============================

(2ai)
(i) They have the same method of preparation
(ii) They have the same chemical properties

(2aii)
(i) Ethane has a single bond while Ethene has a double bond
(ii) They belong to different homogeneous series
(iii) They have different molecular formula and structural formula

(2bi)
(i)HCl
(ii) – It is colourless
– It has an irritating odour
(iii) 2Nacl(aq) + H2SO4(aq) —> Na2SO4(aq) + 2Hcl(g)

(2ci)
Hydrocarbons are compounds having hydrogen and carbon atoms only. Examples are alkanes, alkenes, alkynes etc

(2cii)
(i) Coal
(ii) Crude oil

(2ciii)
C H
83% 100.83
83/12 17/1
6.92/6.92 17/6.92
1 2
Empirical formula = CH2

(2d)
==============================

(3ai)
H2SO4 (aq) + 2KOH(aq) —> K2SO4(aq) + 2H2O(l)

(3aii)
Given, Va = 25.0cm³, Vb = 24.0cm³, Cb = 0.15mol/dm³, Ca =?, Na = 1 , Nb = 2
Using,
CaVa/CbVb = Na/Nb
Ca = CbVbNa/VaNb
Ca = 0.15 × 24.0 × 1/25.0×2
Ca = 3.6/50 = 0.072mol/dm³

(3bi)
(i) 2Mg(s) + CO2(g) —> 2MgO(aq) + C(g)
(ii) This is because magnesium can reduce carbon (iv) oxide to black carbon and producing magnesium oxide

(3bii)
Mg(NO3)2
M of Mg(NO3)2 = 24+(2×14) + (6×16)
= 24 + 28 + 96
= 148g/mol
% of N = 28/148 × 100/1
N = 18.9%

(3ci)
(i) Reaction with KMnO4
(ii) Reaction with bromine water

(3cii)
It turns them colourless

(3d)
Boil the vegetable oil in sodium hydroxide solution, it breaks down releasing the organic acid and the alkanol. The process is known as saponification. The organic ester is immediately neutralized by the sodium hydroxide solution to form the sodium salt of the organic acid which is soap
=================================

(4ai)
(i) Graphite – Hexagonal
(ii) Diamond – Octahedral

(4aii)
Diamond us hard because of the strong force of attraction that hold them together and it can not conduct electricity because all the available electrons are used for bonding while Graphite is soft because it’s particles are in layers and can conduct electricity because not all the electrons are used for bonding

NECO Chemistry Questions & Answers 2022 (OBJ-Essay
NECO 2022 Chemistry Questions and Answers (Essay and

(4bi)
(i) It helps to remove dissolved gases and oxidizes dissolved metals
(ii) It helps to remove objects such as rags, paper, plastics, and clogging of downstream equipment
(iii) It reduces particle concentration in water and minimizes the need for coagulation and flocculation

(4bii)
(i) Calcium tetraoxosulphate (vi)
(ii) Calcium hydrogen trioxocarbonate

(4biii)
(i) Filtration
(ii) Boiling

(4biv)
It has a sweet taste and it builds the shells of lower organisms

(4ci)
The ore (SnO2) is wasted out of the ground with water, powdered, washed and roasted to drive off oxides sulphur, arseric and antimony. The roasted one is now reduced by heating with coke in a reverberatory furnace and molten tin is tapped off from the bottom of the furnace. The tin obtained is impure and it is remelted on a slopping furnace in which the tin melts and run its moulds. The tin obtained is 99.9% pure

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NECO Chemistry Answers 2022 [Theory & Objectives]
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