Waec Physics Practical 2022 Answers – Tues. 31st May 2022

Waec Physics Practical 2022 Answers: The truth is, many secondary schools out there don’t allow their Waec and Neco candidates (exam candidates) to enter the examination hall with their mobile phones, here on Expobite, we are not promising to send you answers at midnight, definitely, that won’t be possible, rather we are promising you 3hrs before the Physics practical exam.

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WAEC PHYSICS PRACTICAL ANSWERS 2022

(NO1)

Graph

(1b and the rest)

(1x)
(Tabulate)
S/N: 1|| 2|| 3|| 4|| 5||

M(g): 20.00|| 40.00|| 60.00|| 80.00|| 100.00||

Z(cm): 40.00|| 35.00|| 30.00|| 25.00|| 20.00||

y(cm): 35.00|| 30.00|| 25.00|| 20.00|| 15.00||

x(cm): 10.00|| 15.00|| 20.00|| 25.00|| 30.00||

V: 0.2857|| 0.5000|| 0.8000|| 1.2500|| 1.2500|| 2.0000||


(1xiv)
(i) I avoided parallax error when taking readings from the meter rule
(ii) I avoided drought by switching off the electric fans

(1bi)
An object is said to be in a stable equilibrium a slight displacement, the object tends to return back to its original position.
°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°

(3)

-Precautions-
(i)I will avoid Parallax error was avoided on ammeter
(ii)I will ensure Key opened when reading was not being taken
(iii)I will avoid sliding of jockey on the potentiometer wire.
Graph

(3b and the Rest)

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Waec Physics practical 2022 is scheduled for Tuesday 31st May 2022 and as a Waec 2022 candidate, you need to get the Physics practice questions and answers on time before the examination, so that you can be able to memorize them beforehand.

Oh yes, 3 hours before the examination is enough time to write all the answers down, or memorize them if you have a retentive memory.

Waec Physics Practical Questions and Answers 2022

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Waec Physics Practical 2022 Exam Date

The Waec Physics practical 2022 examination has been scheduled to hold on Tuesday 31st May 2022 from 09:30 am to 3:30 pm first and second set.

Paper	Start Time	End Time
Physics 3 (Practical) (Alternative A) (1st Set)	09:30 am	12:15 pm
Physics 3 (Practical) (Alternative A) (2nd Set)	12:45 pm	3:30 pm

Countdown to Waec Physics Practical Exam 2022

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Waec Physics Practical Runz 2022 Expo

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Hello, welcome to the Expobite Waec exam help center.

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Waec Physics Practical Specimen 2022

Below is the verified complete Waec 2022 Physics Practical Specimen for SS3 students:

Waec Physics Specimen 2022 (PHYSICS APPARATUS)

QUESTION 1

• Metre rules;
• Set of masses (20 g, 40 g, 60 g, 80 g, and 100 g);
• Knife edge;
• Five pieces of thread each of length about 50cm;
• Weighing balance.

QUESTION 2

• Laboratory thermometer;
• 600 ml supply of water;
• Retort stand and clamp;
• One copper calorimeter, 150 ml capacity; unlagged;
• Glass rod stirrer
• Non-conducting pad for a calorimeter (e.g. cardboard);
• Measuring cylinder (200 ml);
• Stopwatch/clock;
• Bunsen burner/source of heat.

QUESTION 3

• Voltmeter (0 – 2 V);
• Two dry cells (1.5 V each) connected in series (connecting leads should be provided for the battery);
• Potentiometer;
• Key/switch;
• Jockey;
• Metre bridge;
• Connecting wires;
• Ammeter (0 – 2 A).

CONDUCTING THE PRACTICAL PHYSICS TEST

• 3. The following announcement should be made to the candidates at the beginning of the examination:

‘The Examiner does not want you to waste your time because you cannot proceed with an
experiment. Any candidate, therefore, who cannot get on with the experiment after spending 15 minutes on it, may come to me and ask for help.’

• 4. The Physics Teacher should be allowed to give a hint to a candidate who is unable to proceed with the experiment.
• 5. The following regulations must be strictly adhered to.
  • (a) No hint should be announced to the candidates as a whole.
  • (b) A candidate who is unable to proceed and requires assistance must come up to you and state his or her difficulty. The candidate should be told that the Examiner will be informed of any assistance given in this way.
  • (c) A note must be made, on the Report Form, of any assistance given to any candidate, with the name and index number of the candidate.

Click here to see the full Waec Physics specimen with diagrams.

Past Physics Questions and Answers Provided by Expobite

We have been in this since 2014 till date and all these years we have been providing exam candidates with the correct answers to all their exams, below, I will be sharing with you answers from past exam posted here on Expobite.net:

PHYSICS OBJ:
1-10: DCCAACDCCC
11-20: BDACABDCCB
21-30: ACBACCCBAD
31-40: BDDBAACCCA
41-50: CAAABBCBBC

loading…

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PLEASE NOTE: asteric(*) MEANS multiplication(x).

(1)
Original length Lo = 3m
Extension e = 310 = 3*3 = 9m
F×e
F = ke where k = 982.3NM-²
F = 982.3*9 = 8,840.7N
The five that produce the extension F = 8.840.7N

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(2a)
Metal flat plate: It is a collector of heat that converts the radiant solar energy from the sun into heat energy by the process of greenhouse effect.

(2b)
Thermal Insulator: It prevents loss of accumulated heat in the solar collector and thereby improves its absorption efficiency.

(2c)
Tubes: They are use to capture almost all the sun’s energy. It is the most effecient solar collector
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(4)

V∝ Tx μy
LT-∝(MLT-²)x(MLT-¹)y
LT-¹∝ m*L*T-²x x m y L-y
LT-¹∝ m(x+y)L(x-y)T-²x
Comparing
X-y=1
X+y=0
-2x=1
From equation 3
X=½
Putting x = ½ into (eq) 2
y=-½
Equation is
V∝ T½ μ-½
V∝ √T/μ
V= k√T/μ
Where k is constant
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(6)
Angle at horizontal θ = 30°
Time of light , T = 25sec
Velocity of projection u = ?
But T=2using sinθ/g
25= 2u*sin30/10
25=0.5u/5
0.5u=125
U=125/0.5
=250ms-¹

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(8a)
A torque or moment of a couple is the product of one of the forces and the perpendicular distance between the lines of action of the two forces.

(8aii)
(i)The two forces must be equal
(ii)The two forces must be opposite parallel
(iii)They must be equal distance between them

(8bi)
Free fall is defined as the motion of the body where gravity is the only force acting upon it.

(8bii)
Height of tower H = 40.0m
Velocity v = 10.0m/s, time t= ? , g=10.0m/s

Using the relation
S= ut + 1/2gt^2
H= ut + 1/2gt^2
40= 10t + 1/2*10t^2
4= t + t^2/2
= t^2 + 2t – 8=0 ( solving quadratically)
= (t+4)(t-2)=0
t+4=0 or t-2=0
t= -4 or t=2

Therefore time to fall on the ground t=2s

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(1)
Tabulate.
S/N; 1|2|3|4|5|

M|g; 40.0|35.00|30.00|25.00|20.00|

θ°; 41.80|35.70|30.00|24.60|19.47|

ϕ=(90-θ°); 48.20|54.30|60.00|65.40|70.53|

Cosϕ; 0.6665|0.5835|0.5000|0.4163|0.3333|

(1xi)
Slope , S=Δm|g/ΔCosϕ
=(40-20)g/0.6665-0.3333
S= 20g/0.3332=60.024g

(1xii)
K=s/2 =60.024g/g= 30.012g

(1xiii)
-Precautions-
(i) I avoided error due to parallax when reading from the protector
(ii) I ensured that the force board is firmly and correctly clamped to the retort stand

(1)
Graph

(1b)
Coming check by 8;10am
====================================

(3)
Tabulate
S/N; 1|2|3|4|5|

R/Ω; 2.00|4.00|6.00|8.00|10.00|

L/cm; 50.00|66.70|75.00|80.00|83.30|

B/Ω^-¹; 0.500|0.250|0.167|0.125|0.100|

Δ/cm; 1.000|0.499|0.333|0.250|0.200|

(3xiii)
Slope ,S=ΔB/Ω^-¹/ΔΔ/cm =0.5-0.1/1.0-0.2=0.4/0.8=0.5
Slope =0.5Ω^-¹/cm

(3xiv)
K=S^-¹= 1/5=1/0.5Ω^-¹/cm =2Ωcm

(3xv)
-precautions-
(i) I avoided error due to parallax when reading from the potentiometer
(ii) I ensured that the wire are tightly connected.

(3)
Graph

(3bi)
(i) potentiometer give exact value of potential difference while voltmeter draws apart of the current
(ii) potentiometer can be used for measuring the internal resistance of a cell which cannot be done with voltmeter

*NECO 2020 PHYSICS OBJ*
1BCBDBEEDCD
11DACBEBABDE
21CDDDABBBAC
31CDAEBBCCDC
41BEEBDBAEEC
51DDCDADDEBD

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*NECO 2020 SECTION A*

*ANSWERS ONLY 6 FROM THIS SECTION NUMBER 1 IS COMPULSORY*
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PART I

(1a)
(i)printing machine
(ii)sterilizer

(1b)
Diagram (step up transformer)

SEE DIAGRAM

(1c)
1=1.26
t=48005
m=?
z=3.3*10^-⁴g
m=3.3*10^-⁴*1.26*4500
=1.996gram
≅2gram
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(2a)
A system is unstable when displaced, it experiences a net force in the same direction as the displacement from equilibrium. It tends to accelerate away from its equilibrium position if displaced even slightly while for neutral equilibrium, the system is independent of displacement from its original position

SEE DIAGRAM

(2b)
(ii)Low centre of gravity
(ii)Large surface area in contact
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(3a)
Velocity is defined as the rate of change in the displacement of a body it is a vector quantity with the S.I unit of ms-¹

(3b)
DIAGRAM
SEE DIAGRAM
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(4)
At equilibrium position Point B, the body possess maxim kinetic energy. As it moves out to end point A and C. It stops momentarily before changing its direction.

(Diagram)
SEE DIAGRAM
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(5a)
They are both derived quantities

(Diagram)

SEE DIAGRAM

(5b)
67-0/100-0 = x-25/100-25
67/100 = x-25/75
61*3 = 4(x-25)
201 = 4x-100
4x = 201+100
4x = 301
x = 301/4 = 75.25 ohms
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(6a)
(i)violin
(ii)guitar

(6b)
The depth of field of a lens camera is less than that of a pinhole camera
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(7a)
– An amplifier
– A speaker

(7b)
u = 16cm
m = 4=v/u
:. v =4u
v = 4×16 = 64cm
Recall, 1/f = 1/u + 1/v
1/f = 1/16 + 1/64
1/f = 4+1/64
1/f = 5/64
f = 64/5 = 12.8cm
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(8a)
The zinc atoms on the surface of the anode oxidizes I;e they give up both their valence electrons to become positively

(8b)
Diagram
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(9a)
The power factor of a circuit is unity when the apparent power equals or some as the real power

(9b)
V=Vr+Vc
15=12+Vc
Vc=15-12
Vc=3v
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(10a)
(i)Viscosity
(ii)weight
(iii)upthrust

(10bi)
(i)Viscosity; the force in between the layers of flurds this force would tend to reduce the velocity at which the stone moves down till it reach terminal velocity

(ii)weight; is the actual force acting of the stone in the liquid.

(iii)upthrust; is the upward force felt by reply objects in flurd, due to the area displace
=====================================

(11i)
A=9 (molecular mass)
B=6 (atomic mass)
C=0

(11ii)
Z=Energy

(11iii)
Nuclear fusion
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Physics-ExpoBite.Com!

1BCEDBEDBBD
11DEDCAEDCEB
21DDBBCBDBDC
31BEDBBCAEDD
41EDACEECCED
51DCECECDBCB
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Physics-THEORY
(1a)
(i) A multimeter
(ii) Reads if there is short circuit in the electric circuit

(1b)
(i)A simple microscope uses one lens while a compound microscope uses two lens
(ii)A compound microscope produces a higher magnification than that of simple microscope

(1c)
Using M= ZIt
I = M/Zt
I = 450/3.30*10-⁴ *25*60
I = 909A
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(3a)
Range (R) is defined as the horizontal distance from the point of projection to the point where the projectile hits the projection plane again

(3b)
Time of flight: T= 2usinθ/g
sinθ = Tg/2u = 1.5*10/2*12

sinθ = 15/24 = 0.625
θ = sin-¹(0.625)
θ = 38.7°
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(4a)
(i)Flying bullet
(ii)A moving car

(4b)
mgh = mc∆θ
∆θ = gh/c = 10*108/4200
= 0.257°C or 0.257K
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(6a)
A stationary wave is produced by a superposition of two waves of the frequency and amplitude which are exactly out of phase with each other

(6b)
Wavelength = 4/2.5 = 1.6m
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(5a)
Vaporization is the conversion of a substance from the liquid or solid phase into the gaseous (vapour) phase.

(5b)
(i) Deform
(ii) No change
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(8a)
Lost Volt refers to the amount of energy lost (in a battery, generally) to energy resistance of components. It is generally fairly negligible, but to calculate: V=IR
where I is the current and R is resistance.

(8b)
(i) Secondary cell last long and can be used over again and again.

(ii) A secondary cell is rechargeable meaning that the chemical reactions taking place in the cell are reversible and can be carried out in the opposite direction to charge the cell again.
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Expobite Section B.
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(12)

(13)

(14)

(15)

NO 1

NO 1X GRAPH

(1bi)
The period of an oscillatory motion is the time taken for a body to complete one oscillation.

(1bii)
-TABULATE-
(i)Mass is a scalar quantity WHILE weight is a vector quantity.
(ii)The SI unit of mass is the kilogram (kg) WHILE the SI unit of weight is Newton (N).
°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°′
(3av)
Tabulate

S/N ||1 || 2 || 3 || 4 || 5

d(cm) || 80.00|| 70.00 || 50.00 || 40.00 || 30.00

I(A) || 0.30||0.35 || 0.40|| 0.45||0.50 ||

(I)^-¹ ||3.333 ||2.857 ||2.500 || 2.222||2.000 ||

(3avii)
from the graph, Slope s, = ∆d/∆I^-¹
= 71 – 20 ÷ 3 – 1.75
= 51/1.25
= 40.8cmA
Or 0.408Am

(3aviii)
(i) I ensured tight connections
(ii) I avoided error due to parallax while reading the ammeter

(3bi)
(i) Straight at the magnetic field
(ii) The number of turns of it’s coils

(3bii)
Given:
Diameter d, = 0.6cm = 6×10^-³m
Resistivity, e = 1.0×10^-6 Ωm
Resistance R = 4Ω

Using R = eL/A
L=RA/e
= Rπd²/4e
= 4 × 22/7 × 36 × 10^-6 ÷ 4 × 1 × 10^-⁶
= 22/7 × 36
= 113.14m
:. L = 113.14metres

(3a)

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